See image — AITS & Test Series Chemistry Question
Question
See image

Answer: 1.33
💡 Solution & Explanation
[1.33 – 1.34] Sol. Number of triangular faces in truncated cube = 8 Number of octagonal faces in truncated cube = 6 Each corner of the cube will become a triangular face and each square face will become an octahedral face in a truncated solid cube. AITS-OT-I (Paper-1)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 14 Mathematics PART – III Section – A
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes