van der Waal's constant b for a gas is 0.0391 l mole^-1. What is the radius of the gas molecule? β States of Matter and Gaseous State Chemistry Question
Question
van der Waal's constant b for a gas is 0.0391 l mole^-1. What is the radius of the gas molecule?
Answer: B
π‘ Solution & Explanation
b = 4 * N_A * (4/3)*Ο*r^3 => 0.0391 * 10^-3 = 4 * 6.022*10^23 * 4.188 * r^3 => r^3 = 3.87 * 10^-27 => r = 1.57 * 10^-9 m = 1.57 Γ .
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