To a solution of acetic acid, solid sodium acetate is gradually added. When 'x g' of the salt has been added, the pH has a certain value. When total 'y g' of the salt has been added, the pH has been f

Question

To a solution of acetic acid, solid sodium acetate is gradually added. When 'x g' of the salt has been added, the pH has a certain value. When total 'y g' of the salt has been added, the pH has been further raised by 0.6 units. What is the ratio of x:y? (log 3.98 = 0.6)

Prashant Kotian · Accepted Answer

Correct answer: B. According to the Henderson-Hasselbalch equation: pH = pKa + log([Salt]/[Acid]). Initially: pH1 = pKa + log(x / (M_acid × V)). After adding y g: pH2 = pKa + log(y / (M_acid × V)). We are given: pH2 = pH1 + 0.6 => pH2 - pH1 = 0.6 = log(y / x). Since log 3.98 = 0.6, we have y / x = 3.98 => x:y = 1 : 3.98.

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