An acidified manganate solution undergoes disproportionation reaction. The spin-only magnetic moment — d and f Block Elements Chemistry Question

💡 Solution & Explanation

**Step 1: Identify the disproportionation reaction** Acidified manganate (MnO₄²⁻, Mn⁶⁺) undergoes disproportionation: 2MnO₄²⁻ + 4H⁺ → MnO₄⁻ + MnO₂ + 2H₂O Products: MnO₄⁻ (Mn⁷⁺) and MnO₂ (Mn⁴⁺) **Step 2: Identify the higher oxidation state product** The higher oxidation state is Mn⁷⁺ in MnO₄⁻ (permanganate ion). **Step 3: Determine electron configuration of Mn⁷⁺** Mn (Z = 25): [Ar]3d⁵4s² Mn⁷⁺: [Ar]3d⁰ (all d-electrons removed) **Step 4: Calculate unpaired electrons** With 3d⁰ configuration, there are **0 unpaired electrons**. **Step 5: Apply spin-only magnetic moment formula** μ = √[n(n+2)] B.M., where n = number of unpaired electrons μ = √[0(0+2)] = √0 = 0 B.M. Therefore, the answer is 0.00.