See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

  2 3 2 3Cl 6NaOH conc. 5NaCl NaClO H O       2 3 2 3Br 6NaOH conc. 5NaBr NaBrO 3H O       2 3 2 3I 6NaOH conc. 5NaI NaIO 3H O     2 4 3 2 2 3H O P Conc.3NaOH PH 3NaH PO           3 3 3 2 2 2 2 CH CHCHO Conc.NaOH CH CHCOO Na CH CHCH OH      3 HCHO Conc.NaOH HCOO Na CH OH      Total 6 compound undergo disproportionation. So x= 6 & y= 5 x/y=1.2