The OH– concentration in a mixture of 5.0 mL of 0.0504 M NH4Cl and 2 mL of 0.0210 M NH3 — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

[NH4Cl] = [NH4+] = 0.0504 M V = 5.0 mL [NH3] = 0.0210 M V = 2.0 mL Kb = ] NH [ ] OH ][ NH [ 4   [OH–] = ] NH [ ] NH [ K 3 b   = 0504 . 2 . 10 . 5      = 3 × 10–6 M