See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Sol.    2 A g 2B g AB g       2 c 2 AB 1 K 2 A B      2 2 2 AB 1 AB 4 moles 2 2 2     Now, B = 4 moles Let y moles of AB2 is added.    2 4 y 1 2 2 4    y 12  