The volume (in mL) of 0.1 N NaOH required to neutralise 10 mL of 0.1 N phosphinic acid is …………….. . — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1: Identify the acid type and its neutralization equation** Phosphinic acid (H₃PO₂) is a monobasic acid, meaning it has only ONE ionizable hydrogen atom: H₃PO₂ + NaOH → NaH₂PO₂ + H₂O **Step 2: Apply the neutralization formula** For acid-base neutralization: N₁V₁ = N₂V₂ Where: - N₁ = normality of acid = 0.1 N - V₁ = volume of acid = 10 mL - N₂ = normality of base = 0.1 N - V₂ = volume of base = ? **Step 3: Substitute values** 0.1 × 10 = 0.1 × V₂ **Step 4: Solve for V₂** 1 = 0.1 × V₂ V₂ = 1/0.1 = 10 mL **Step 5: Verify using equivalents** Equivalents of acid = 0.1 N × 10 mL = 1 meq Equivalents of NaOH needed = 1 meq Volume of NaOH = 1 meq ÷ 0.1 N = 10 mL ✓ Therefore, the answer is 10.00.