Dibutylphthalate is often used as a mono-meter fluid. It has a density of 1.047 g/ml. How many torrs β States of Matter and Gaseous State Chemistry Question
Question
Dibutylphthalate is often used as a mono-meter fluid. It has a density of 1.047 g/ml. How many torrs are represented by 1 mm of this fluid?
Answer: A
π‘ Solution & Explanation
The pressure exerted by a liquid column is given by P = d * g * h. For equal pressure, d_fluid * h_fluid = d_Hg * h_Hg. Comparing the fluid with mercury (density = 13.6 g/ml): 1.047 g/ml * 1 mm = 13.6 g/ml * h_Hg. Therefore, h_Hg = 1.047 / 13.6 = 0.077 mm of Hg. Since 1 mm of Hg = 1 torr, 1 mm of dibutylphthalate represents 0.077 torr.
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