0.1 M solution of KI reacts with excess of H2SO4 and KIO3 solutions. According to equation 5I– + – I — JEE Mains Chemistry Past Papers Chemistry Question
Question
0.1 M solution of KI reacts with excess of H2SO4 and KIO3 solutions. According to equation 5I– + – IO + 6H+ 3I2 + 3H2O Identify the correct statements: (A) 200 mL of KI solution reacts with 0.004 mol of KIO3 (B) 200 mL of KI solution reacts with 0.006 mol of H2SO4 (C) 0.5 L of KI solution produced 0.005 mole of I2 (D) Equivalent weight of KIO3 is equal to weight Molecuar Choose the correct answer from the options given below : (A) (C) and (D) only (B) (B) and (C) only (C) (A) and (D) only (D) (A) and (B) only
💡 Solution & Explanation
(A) 5– + O3– + 6H+ 32 + 3H2O nK = 1 × 0.1 = 0.02 – – O n n = . 02 . = 5 (D) – + O3– 2 +5 x = 5 E = M/5 Ans. (A, D) | JEE(Main) 2025 | DATE : 29-01-2025 (SHIFT-2) | PAPER-1 | CHEMISTRY PAGE # 6