At the point of intersection of the two curves shown, the concentration of B is given as (A -> nB) — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

For the reaction A -> nB: let the initial concentration of A be A_0, and that of B be 0. At any time t, if x is the concentration of A that has reacted, [A] = A_0 - x and [B] = nx => x = [B]/n. Thus, [A] = A_0 - [B]/n. At the intersection of the two curves, [A] = [B]. Substituting [A] = [B]: [B] = A_0 - [B]/n => [B](1 + 1/n) = A_0 => [B]((n+1)/n) = A_0 => [B] = n*A_0/(n+1).