See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1: Identify the parent chain/ring. The compound is a cyclohexane ring, so the parent name is cyclohexanol (since OH is the principal characteristic group). Step 2: Identify all substituents. Looking at the structure: there is an OH group, a Cl atom, a Br atom, and a vinyl (ethenyl, CH=CH2) group attached to the ring. Step 3: Number the ring to give the principal characteristic group (OH) the lowest possible locant. The OH receives C1. Step 4: Assign locants to remaining substituents by going in the direction that gives the next substituents the lowest set of locants. From C1 (OH), Cl is on the adjacent carbon in one direction (C2), Br is on the next carbon (C3), and the ethenyl group is on the other adjacent carbon to C1 (C6). The locant set {1,2,3,6} is preferred over {1,2,4,5} which confirms the numbering. Step 5: Alphabetize substituents for the name: bromo (C3), chloro (C2), ethenyl (C6), then -ol (C1). Step 6: Assemble the name: 3-bromo-2-chloro-6-ethenylcyclohexan-1-ol, commonly written as 3-bromo-2-chloro-6-ethenylcyclohexanol. No other options are present to eliminate, but alternative numbering directions would give higher locant sets and are therefore incorrect per IUPAC rules. Therefore, the correct answer is 3-bromo-2-chloro-6-ethenylcyclohexanol.