Among following molecule N—Si bond length is shortest : — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Step 1: Analyze the structure and count the individual σ and π bonds in each part of the organometallic complex: `(NC)_2C=C(M(CO)_3)(C_2H_5)`. Step 2: Count the bonds: The two cyano groups contribute 4 σ and 8 π bonds. The double bond C=C contributes 1 σ and 1 π bond. The C-M single bond is 1 σ bond. The three carbonyl ligands (-CO) on the metal contribute 3 M-CO σ bonds, and 3 C≡O triple bonds contributing 3 σ and 6 π bonds. The ethyl group (-C_2H_5) contributes 1 M-C, 1 C-C, and 5 C-H σ bonds (total 7 σ bonds). Step 3: Total σ bonds = 4 (cyano) + 1 (C=C) + 1 (C-M) + 6 (CO) + 7 (ethyl) = 19. Total π bonds = 4 (cyano) + 1 (C=C) + 6 (CO) = 11. Therefore, there are 19 σ and 11 π bonds, which corresponds to option (a).