The lanthanoid that does NOT show +4 oxidation state is : (A) Ce (B) Tb (C) Dy (D) Eu — JEE Mains Chemistry Past Papers Chemistry Question
Question
The lanthanoid that does NOT show +4 oxidation state is : (A) Ce (B) Tb (C) Dy (D) Eu
Answer: D
💡 Solution & Explanation
Cu(z = 63) = 4F76s2 Dy(z = 66) = 4F106s2 Tb(z = 65) = 4F96s2 Ce(58) = 4F15d16s2 Dy, Tb and Ce show +4 oxidation state while Eu do not show +4 oxidation state.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes