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AITS & Test SerieshardMCQ SINGLE

Question

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Answer: C

💡 Solution & Explanation

At anode: ½H2(g)  H+(aq.) + e At cathode: AgCl(s) + e  Ag(s) + Cl(aq.) ½H2(g) + AgCl(s)  H+(aq) + Cl(aq) + Ag(s).

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