Consider the successive ionisation energy for an element 'A'. IE1, IE2, IE3, IE4, IE5 are 100 eV, 15 β Periodic Table and Periodicity Chemistry Question
Question
Consider the successive ionisation energy for an element 'A'. IE1, IE2, IE3, IE4, IE5 are 100 eV, 150 eV, 181 eV, 2000 eV, 2200 eV. Select correct statement(s) for element 'A' :
Answer: A,B,C,D
π‘ Solution & Explanation
Step 1: Identify the element 'P' with configuration [Xe] 4f14 5d1 6s2. This corresponds to Lutetium (Z=71), the last lanthanide. Step 2: The highest principal quantum number is n=6, indicating it is in the 6th period. Lanthanides and Lutetium are positioned in Group 3 of the d-block. Step 3: Conclude that element 'P' belongs to the 6th period and 3rd group, which is option (c).
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