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AITS & Test SerieshardNUMERICAL

Question

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Answer: 4

💡 Solution & Explanation

o 0 o 2v sin37 3 T sec g cos 37 2   V0 cos 37o × 2 2 o o 3 1 3 3 1 3 g sin 37 6 V g sin 37 2 2 2 2 2 2                   V = 4

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