See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

   X g 2Y g Z g t 0 3 t 10s 3 a 2a a      1 1 2 2 2 1 r P M 1 r 2 P M   For More Material Join: @JEEAdvanced_2024 AITS-FT-XI-PCM(Sol.)-JEE(Main)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9 1 3 a 4 2 2a 16   1 3 a 1 2 2a 2    3 – a = 2a a = 1 T n 3 a 2a a     = 5 nRT 5