From the magnetic behaviour of [NiCl4]2– (paramagnetic) and [Ni(CO)4] (diamagnetic), choose the correct geometry and oxidation state. (A) [NiCl4]2– : Ni, tetrahedral [Ni(CO)4] : Ni(0), tetrahedral (B)

Question

From the magnetic behaviour of [NiCl4]2– (paramagnetic) and [Ni(CO)4] (diamagnetic), choose the correct geometry and oxidation state.

(A) [NiCl4]2– : Ni, tetrahedral [Ni(CO)4] : Ni(0), tetrahedral
(B) [NiCl4]2– : Ni, tetrahedral [Ni(CO)4] : Ni, square planar
(C) [NiCl4]2– : Ni, square planar [Ni(CO)4] : Ni(0), square planar
(D) [NiCl4]2– : Ni(0), tetrahedral [Ni(CO)4] : Ni(0), square planar

Prashant Kotian · Accepted Answer

Correct answer: A. [NiCl4]2–, Ni+2 = [Ar]3d8, 4s0 (wfl) sp3 tetrahedral [Ni(CO)4], Ni0, sfl therefore after rearrangement 3d10, 4s0  sp3, tetrahedral.

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