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AITS & Test SerieshardNUMERICAL

Question

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Answer: 2.50

💡 Solution & Explanation

1 0 f(x)dx 1   1 0 2 0 1 2 0 1 2 1 f(2x)dx 3 Let 2x t 2dx dt f(t)dt 6 f(t)dt f(t)dt 6 1 5 f(x)dx 2 2                 

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