Reversible A ⇌ B; δ H = -2 kcal. Pre-exponential factors same. E_a(backward) = 8 kcal/mol. Correct i — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

E_af = E_ab + δ H = 8 + (-2) = 6 kcal/mol (A correct). Fraction A: e^(-6000/R*500) = e^(-6000/1000) = e^-6 (B correct, using R=2 cal/(mol K)). Fraction B (backward): e^(-8000/1000) = e^-8 (C correct). $K_{eq}$ = (A/A)*e^(-(E_af-E_ab)/RT) = e^(-(-2000/1000)) = e^+2 (not e^-2; D incorrect).