A person's wound was exposed to some bacteria and then bacterial growth started to happen at the same place. The wound was later treated with some antibacterial medicine and the rate of bacterial deca

Question

A person's wound was exposed to some bacteria and then bacterial growth started to happen at the same place. The wound was later treated with some antibacterial medicine and the rate of bacterial decay (r) was found to be proportional with the square of the existing number of bacteria at any instance. Which of the following set of graphs correctly represents the 'before' and 'after' situation of the application of the medicine ? [Given : N = No. of bacteria, t = time, bacterial growth follows 1st order kinetics.]

(B) | JEE(Main) 2025 | DATE : 07-04-2025 (SHIFT-1) | PAPER-1 | CHEMISTRY PAGE # 7

Prashant Kotian · Accepted Answer

Correct answer: C. Before applying medicine dt dA = K[A] (first order growth) (Rate law) A A = N N = ekt * After applying medicine Active Bacteria  Inactive Bacteria (A) (B) r = dt dA = K[A]2 (Rate law) y = kx2 parabola

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