Ag2CO3↓ + 2HCl -> AgCl↓ + CO2↑ + H2O — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Silver carbonate, Ag2CO3↓, is an insoluble precipitate. Step 2: Upon addition of hydrochloric acid (HCl), it reacts to produce highly insoluble silver chloride, AgCl↓ (which has a lower solubility than silver carbonate), while carbonate decomposes to CO2↑ and H2O. Step 3: Since one solid precipitate (Ag2CO3↓) is converted into another solid precipitate (AgCl↓), this is classified as a precipitate exchange reaction (type C), matching option (c).