See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Tf = kf × Molality  1 180 g) (in glucose of weight 1000 1 kg) (in water of mass glucose of moles of number molality k T f f        weight of glucose (in g) = 0.18 g For More Material Join: @JEEAdvanced_2025 AITS-FT-VII-PCM(Sol.)-JEE(Main)/2025 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 7