See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

C H C H3 CH3CH2 CH2 Br I Acetone   Leaving group is not at chiral carbon. C H C H3 CH3CH2 CH2 I I is a strong nucelophile and is taken in polar aprotic solvent. Thus N S 2 reaction. As there is no attack on chiral centre, configuration of the reactant and product is same. For More Material Join: @JEEAdvanced_2024 Rankers Academy JEE AITS-FT-X-PCM(Sol.)-JEE(Main)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 12