For the cyclic process given below, which of the following relations are correct? Path 1β2 is Revers β Thermodynamics and Thermochemistry Chemistry Question
Question
For the cyclic process given below, which of the following relations are correct? Path 1β2 is Reversible, Path 2β1 is Irreversible.

Answer: A,D
π‘ Solution & Explanation
Since S is a state function, Ξ S along the reversible path 1β2 equals $S_2$-S1 = int_1^2 dq_rev/T (A correct). For irreversible path 2β1: S1-$S_2$ > int_2^1 dq_irr/T (B incorrect). For the entire cycle, Ξ S_cycle=0 (state function). By Clausius inequality, for a cycle with an irreversible step: oint dq/T < 0, so int_1^2 dq_rev/T + int_2^1 dq_irr/T < 0. Thus Ξ S_cycle = 0 > int_1^2 dq_rev/T + int_2^1 dq_irr/T (D correct, C incorrect).
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