If x and y are total number of electrons which are present in non-axial and axial set of d-orbitals respectively in Ni cation of [Ni(DMG)2], then calculate value of .

Question

If x and y are total number of electrons which are present in non-axial and axial set of d-orbitals respectively in Ni cation of [Ni(DMG)2], then calculate value of $2x^2 / y$.

Prashant Kotian · Accepted Answer

Correct answer: **ANSWER: 36**<BR>SOLUTION: NI2+ IN [NI(DMG)2] IS $3D^8$ AND $DSP^2$ HYBRIDIZED. DISTRIBUTION OF $D$-ELECTRONS: NON-AXIAL ORBITALS ($D_{XY}, D_{YZ}, D_{ZX}$) CONTAIN $2+2+2 = 6$ ELECTRONS, SO $X = 6$. AXIAL ORBITALS ($D_{Z^2}, D_{X^2-Y^2}$) CONTAIN $2+0 = 2$ ELECTRONS, SO $Y = 2$. THEREFORE, $2(6)^2 / 2 = 36$.. Step 1: Metal carbonyls are highly stable when the central metal atom achieves the Effective Atomic Number (EAN) of the next noble gas (for the 3d transition series, Krypton with EAN = 36). Step 2: Calculate the EAN of Mn in Mn(CO)5: 25 (atomic number of Mn) - 0 + 2 * 5 = 35. Step 3: Because Mn(CO)5 is one electron short of the stable EAN of 36, it has a strong tendency to accept one electron (undergo reduction) to form the stable [Mn(CO)5]^- ion, making it act as an oxidizing agent. This corresponds to option (a).

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