See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

           2 2 2 BaF s Ba aq 2F aq 's' be the solubilityof BaF s 2s  2 2 2 7 2 4 2 4 eq Let y mol / lit. of Ba is Ba C O BaC O s K 10 left after reaching equilbrium y