Quantitative analysis of an organic compound (X) shows following % composition C : 14.5% Cl : 64.46% H : 1.8% (Empirical formula mass of the compound (X) is _________ × 10–1) [Given molar mass in g mo

Question

Quantitative analysis of an organic compound (X) shows following % composition C : 14.5% Cl : 64.46% H : 1.8% (Empirical formula mass of the compound (X) is _________ × 10–1) [Given molar mass in g mol–1 of C : 12, G : 1, O : 16, Cl : 35.5]

Prashant Kotian · Accepted Answer

Correct answer: .. Element % Mole Simple ratio Simplest whole no. rate C 14.5 5 . = 1.20 2 Cl 64.46 . 46 . = 1.82 1.5 H 1.8       8 . = 1.8 1.5 O 20.04 04 . = 1.25 2 Empirical formula = C2Cl3H3O2 Empirical formula mass = 165.5 = 1655 × 10–1

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