An ideal gas is taken reversibly from state A (P, V) to the state B (0.5P, 2V) along a straight line — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

For the straight line path: P = 1.5P0 - 0.5(P0/V0)V. Work done is the trapezoidal area = 0.75PV, which exceeds the isothermal work (0.693PV). T is ∝ PV, which is quadratic in V (parabola), so T goes through a maximum.