JEE Mains Chemistry Past PapershardMCQ SINGLE

The equilibrium constant for the reaction 2 1 SO g SO g O g is KC = 4.9 × 10–2. The value of KC for JEE Mains Chemistry Past Papers Chemistry Question

Question

The equilibrium constant for the reaction 2 1 SO g SO g O g is KC = 4.9 × 10–2. The value of KC for the reaction given below is 2 2SO g O g 2SO g is (A) 4.9 (B) 41.6 (C) 49 (D) 416

Answer: D

💡 Solution & Explanation

2 C C 1 K' K 4.9 10               K'C = 416.49

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