In a solid AB, having the structure, A atoms occupy the corners of the cubic unit cell. If all the face-centred atoms along one of the axes are removed, then resulting stoichiometry of the solid is

Question

In a solid AB, having the $NaCl$ structure, A atoms occupy the corners of the cubic unit cell. If all the face-centred atoms along one of the axes are removed, then resulting stoichiometry of the solid is

Prashant Kotian · Accepted Answer

Correct answer: D. Total A (FCC): 8 corners + 6 face-centers. Removing face-center atoms along one axis removes 2 face atoms. Remaining A = 8*(1/8) + 4*(1/2) = 3 atoms. B (octahedral voids) remains 4 atoms. Stoichiometry A3B4.

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