See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(for Q. 33 and 34):   4 2 7 2 2 3 2 2 NH Cr O N Cr O 4H O     4 3 2 2 NH NO N O 2H O      3 2 2 2 Hg NO Hg 2NO O     Total number of moles of diatomic gases (X)     2 2 N 1 mole O 1 mole   = 2 moles Volume 2