What is the number of unpaired electron(s) in the highest occupied molecular orbital of the following species : N2 ; N2+ ; O2 ; O2+ ? (A) 0,1,2,1 (B) 2,1,2,1 (C) 0,1,0,1 (D) 2,1,0,1

Question

What is the number of unpaired electron(s) in the highest occupied molecular orbital of the following species : N2 ; N2+ ; O2 ; O2+ ?

(A) 0,1,2,1
(B) 2,1,2,1
(C) 0,1,0,1
(D) 2,1,0,1

Prashant Kotian · Accepted Answer

Correct answer: A. Species Number of unpaired electron (N2) : (1s)2 (*1s)2 (2s)2 (*2s)2 (2p2x = 2p2y ) 2pz)2 (N2+) : (1s)2 (*1s)2 (2s)2 (*2s)2 (2p2x = 2p2y ) 2pz)1 (O2) : (1s)2 (*1s)2 (2s)2 (*2s)2 (2pz)2 (2p2x = 2p2y) (*2px1 = *2p1y) (O2+): (1s)2 (*1s)2 (2s)2 (*2s)2 (2pz)2 (2p2x = 2p2y) (*2px1 = *2p0y)

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