What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg? (Assume dilute solution is being formed) Given : Vapour pressure of pure water is 54.2 mm Hg at r

Question

What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg? (Assume dilute solution is being formed) Given : Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is 180 g mol–1.

(A) 4.69 g
(B) 2.59 g
(C) 3.59 g
(D) 3.69 g

Prashant Kotian · Accepted Answer

Correct answer: D. For a solution N n P P P s s A   18 / 180 / 54 . w   Amount of glucose w = 54 200 = 3.69 g

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