By which of the following reagents can a sublimate of HgCl2 be distinguished from NH4Cl ? — Qualitative and Quantitative Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Adding HCl to a solution containing Group I cations (Ag+, Pb2+, Hg22+) precipitates them as insoluble white chlorides. Step 2: Among these chlorides, lead(II) chloride (PbCl2) dissolves readily in hot water because of its high endothermic dissolution character. Step 3: Therefore, the metal ion is Pb2+, which corresponds to option (c).