See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Given mY = 2mZ . . . (i) Urms of ‘Y’ = 2  Urms of Z . . . (ii) and no. of molecules of Y = No. of molecules of ‘Z’ . . . (iii) 2 1 3 Y Y Y Y rms P V M U   PZVZ = 2 1 3 Z Z rms M U AITS-FT-VIII-PCM(Sol.)-JEE(Main)/20 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 8  2 2 Y Y Y Y Z Z Z Z P V M U P V M U   . . . . . . (iv)  Given VY = VZ . . . . . . (v) By equation 1, 2, 3, 4, 5, 2 2 (2) 8 Y Z P P   