For the reaction: (g) + 3(g) - 2(g) under certain conditions of temperature and partial pressure of the reactants, the rate of formation of is 10^-3 kg h^-1. The rate of consumption of under same con

Question

For the reaction: $N_2$(g) + 3$H_2$(g) -> 2$NH_3$(g) under certain conditions of temperature and partial pressure of the reactants, the rate of formation of $NH_3$ is 10^-3 kg h^-1. The rate of consumption of $H_2$ under same condition is

Prashant Kotian · Accepted Answer

Correct answer: B. Rate of reaction = -1/3 d[]/dt = +1/2 d[]/dt => Rate of consumption of (in mol/h) = 3/2 * Rate of formation of . Moles of formed per hour = 10^-3 kg / (17 × 10^-3 kg/mol) = 1/17 mol/h. Moles of consumed per hour = 3/2 * (1/17) = 3/34 mol/h. Mass of consumed per hour = (3/34 mol/h) * 2 g/mol * 10^-3 kg/g = 6/34 × 10^-3 kg/h = 1.76 × 10^-4 kg/h.

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