[Four-digit Integer] A volume of 585 ml of 1%(w/w) solution of density 1.2 g/ml is required for complete coagulation of 200 ml of a gold sol, in two hours. The coagulation value of is

Question

[Four-digit Integer] A volume of 585 ml of 1%(w/w) $NaCl$ solution of density 1.2 g/ml is required for complete coagulation of 200 ml of a gold sol, in two hours. The coagulation value of $NaCl$ is

Prashant Kotian · Accepted Answer

Correct answer: 0600. Mass of solution = 585 * 1.2 = 702 g. Mass of = 1% of 702 = 7.02 g. Moles of = 7.02 / 58.5 = 0.12 mol = 120 mmol. Coagulation value = millimoles of electrolyte per litre of sol = 120 / 0.2 = 600 mmol/L. Written as zero-padded four-digit: 0600.

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