What is the magnitude of work performed by one mole of the gas when its volume increases 8 times if — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

$C_{v,m}$ = 1.5R => (γ-1)/2 = 1/3. T2/T1 = (V1/V2)^(1/3) = (1/8)^(1/3) = 1/2. T2 = 150 K. ΔU = 1 × 1.5R × (-150) = -225R. q = -ΔU = +225R. w = ΔU - q = -450R. Magnitude = 450 × 2 cal = 900 cal.