See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

3 CH OH V = 30 mL 2 5 C H OH V = 60 mL d = 0.8 g/cc d = 0.92 g/cc W = 0.8  30 = 24 g W = 60  0.92 = 55.2 g n = 24 32 = 0.75 n = 55.2 46 = 1.2 Total moles = 0.75 + 1.2 = 1.95 Solute = CH3OH, Solvent = C2H5OH Molarity = 0.75  1000 90 = 8.33 Molality = 0.75 1000