Na2O2 P + Q
Na2O2 P + R + S
Calculate sum of bond order between same bonded atoms in Q and R compounds.

Question

Na2O2 $\xrightarrow{ ext{Water, } 0^\circ ext{C}}$ P + Q
Na2O2 $\xrightarrow{ ext{Water, } 25^\circ ext{C}}$ P + R$\uparrow$ + S
Calculate sum of bond order between same bonded atoms in Q and R compounds.

Prashant Kotian · Accepted Answer

Correct answer: 3

**SOLUTION:**
NA2O2 $\XRIGHTARROW{\TEXT{H}_2\TEXT{O, } 0^\CIRC\TEXT{C}}$ NAOH (P) + H2O2 (Q)
NA2O2 $\XRIGHTARROW{\TEXT{WATER, } 25^\CIRC\TEXT{C}}$ NAOH (P) + O2$\UPARROW$ (R) + H2O (S)
BOND ORDER OF [O-O] IN H2O2 = 1.0
BOND ORDER OF [O-O] IN O2 = 2.0
SUM OF BOND ORDER BETWEEN SAME BONDED ATOMS IN Q AND R COMPOUNDS = 1 + 2.0 = 3.0. Step 1: Sodium bicarbonate (NaHCO3) is an ionic compound composed of sodium cations (Na+) and bicarbonate anions (HCO3-), which are held together by ionic bonds. Step 2: Inside the polyatomic bicarbonate anion, the hydrogen, carbon, and oxygen atoms are linked through covalent bonds. In the solid crystal lattice, these bicarbonate units are further held together by intermolecular hydrogen bonding. Step 3: Consequently, all three types of bonds (ionic, covalent, and hydrogen bonds) are present in sodium bicarbonate, making option (d) the correct choice.

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