Consider the following data: Heat of formation of CO2(g) = –393.5 kJ mol–1 Heat of formation of H2O(l) = –286.0 kJ mol–1 Heat of combustion of benzene = –3267.0 kJ mol–1 The heat of formation of benze

Question

Consider the following data: Heat of formation of CO2(g) = –393.5 kJ mol–1 Heat of formation of H2O(l) = –286.0 kJ mol–1 Heat of combustion of benzene = –3267.0 kJ mol–1 The heat of formation of benzene is____________ kJ mol–1 (Nearest integer)

Prashant Kotian · Accepted Answer

Correct answer: .. C6H6 + O2(g)  6CO2(g) + 3H2O(l) HºC = –3267 kJ/mol HC = 6HF (CO2,g) + 3HF(H2O,l) – HF(C6H6) – HF(C6H6) – HF(O2,g) –3267 = 6(–393.5) + 3(–286) – HF(C6H6) HF(C6H6) = – 3219 + 3267 = 48 kJ/mol.

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