The radius of the 2nd orbit of Li2+ is x. The expected radius of the 3rd orbit of Be3– is : (A) 16 x — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

R = 0.529 × Z n2 n Li ) r(   = 0.529 × ) ( = x n Be ) r(   = 0.529 × (3)2 n Be n Li ) r( ) r( 2     = ) ( r ) ( r 0 0   n Be ) r( x   = 16  n Be ) r(   = 16 x