Consider the following three compounds (i) , (ii) and (iii) , where central atom A is 15th group element and their maximum covalency is 3n. If total number of proton in surrounding atom is and value o

Question

Consider the following three compounds (i) $AX_{2n}^{n-}$, (ii) $AX_{3n}$ and (iii) $AX_{4n}^{n+}$, where central atom A is 15th group element and their maximum covalency is 3n. If total number of proton in surrounding atom $X$ is $n$ and value of $n$ is one, then calculate value of "$x^3 + y^2 + z^n$". (Where $x, y$ and $z$ are total number of lone pair at central atom in compound (i), (ii) and (iii) respectively).

Prashant Kotian · Accepted Answer

Correct answer: 9

**SOLUTION:** IF $N=1$, THEN $X=H$; $A=N$ (15TH GROUP). THE COMPOUNDS ARE (I) $NH_2^-$, (II) $NH_3$, (III) $NH_4^+$.
LONE PAIRS: $X=2$, $Y=1$, $Z=0$.
$X^3 + Y^2 + Z^N = (2)^3 + (1)^2 + (0)^1 = 9$.. Step 1: Determine the number of π-bonds in each thionic/sulfur oxyacid species by drawing their Lewis structures to satisfy octets/valencies (S exhibits variable valency up to 6). Step 2: Calculate the π-bonds: (II) H2S2O3 has 2 π-bonds; (III) H2S2O5 has 3 π-bonds; (I) H2S2O6 has 4 π-bonds. Step 3: Order the compounds by increasing number of π-bonds: II (2) < III (3) < I (4), which corresponds to option (c).

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