Consider a weak base 'B' of pKb = 5.699. 'x' mL of 0.02 M HCl and 'y' mL of 0.02 M weak base 'B' are — JEE Mains Chemistry Past Papers Chemistry Question
Question
Consider a weak base 'B' of pKb = 5.699. 'x' mL of 0.02 M HCl and 'y' mL of 0.02 M weak base 'B' are mixed to make 100 mL of a buffer of pH 9 at 25ºC. The values of 'x' and 'y' respectively are: [Given: log 2 = 0.3010, log 3 = 0.4771, log 5 = 0.699] (A) x y 11.1 88.9 (B) x y 42.7 57.3 (C) x y 14.3 85.7 (D) x y 85.7 14.3
Answer: C
💡 Solution & Explanation
HCl + B BH + + Cl – 0.02M 0.02M x ml y ml tf 0 0.02y–0.02x 0.02x b Salt pOH pK log Base Salt 5.699 log Base x y x 6x = y 7x = 100 x ml & y ml
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