What should be the minimum volume of the room, if no liquid water is to be present finally in the ro — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

For all 5.0 kg (5000 g) of water to vaporize: Moles of water n = 5000 / 18 = 277.78 mol. The volume required at saturated vapour pressure (P = 0.04 atm) is: V = nRT / P = 277.78 × 0.08 × 300 / 0.04 = 6666.72 / 0.04 = 166,668 L = 166.67 m^3.