See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

1 2 3K 2 2K 3  2 3 2K 3 K 4  1 2 K 4 K 9  2 3 K 3 9 K 8 24   1 2 3 K : K : K 4 : 9 : 24 1 1 2 2 3 3 1 2 3 K E K E K E E K K K      = 4x 8 9x 6 24x 3 37x      = 32 54 72 4 37   