Equal masses of ethane and hydrogen are mixed in an empty container at 25°C. The fraction of the tot — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Let the mass of each gas be w. Moles of $C_2H_6$ = w/30 [9]. Moles of $H_2$ = w/2 [9]. Pressure fraction of $H_2$ = n($H_2$) / [n($H_2$) + n($C_2H_6$)] = (w/2) / [w/2 + w/30] = (1/2) / (16/30) = 15/16 [9].