See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

HCl + NH4OH  NH4Cl + H2O H = –12.27 H+ + Cl– + NH4OH  4 NH + Cl– + H2O H = –12.27 …1 NH4OH  4 NH + OH– H = x … 2 From equation (1) and (2) H+ + OH–  H2O H = –12.27 – x We know that –12.27 – x = –13.7 X = 1.43 Kcal